With Pointers to determine size, why not come?-CodePudding

# include
Void adjust (int * (p1, p2 int *)
{
Int * p3;
If (* p1 & lt; * (p2)
{
P3=p;
P1=p2;
The p2=p3;
}
}
Int main ()
{
Math1 int a1, a2, * and * math2;
Math1=& amp; A1.
Math2=& amp; A2.
The scanf (" % d % d \ n ", & amp; A1, & amp; A2);
Adjust (math1, math2);
Printf (" % d % d \ n ", * math1, * math2);
return 0;

}

CodePudding user response:

Reference:

 # include 
Void adjust1 (int * (p1, p2 int *)//pointer p1 p2 scope in this function, so to change their values, 
//not back to the math1 math2, so is invalid, 
{
Int * p3; 
If (* p1 & lt; * (p2) 
{
P3=p; 
P1=p2; 
The p2=p3; 
} 
} 

Void adjust2 (int * (p1, p2 int *)//to the pointer points to the value of the operation is effective 
{
Int p3; 
If (* p1 & lt; * (p2) 
{
P1 p3=*; 
* p1=* (p2); 
* the p2=p3; 
} 
} 

Int main () 
{
Math1 int a1, a2, * and * math2; 
Math1=& amp; A1. 
Math2=& amp; A2. 
The scanf (" % d % d ", & amp; A1, & amp; A2);//the scanf (" % d % d \ n ", & amp; A1, & amp; A2); There is much more '\ n' 

Adjust1 (math1, math2); 
Adjust1: printf (" % d % d \ n ", * math1, * math2); 

Adjust2 (math1, math2); 
Adjust2: printf (" % d % d \ n ", * math1, * math2); 

return 0; 
}

CodePudding user response:

In-depth study Pointers and references, as well as the function scope and return values