Could you tell me the following PI () function checks whether the can satisfy
PI/2=1 + 1/3 + 1/3 + 1/3 2/5 * * * 2/5 3/7 +...
Double PI (double t)
{
Double sum=1, m=1, n.
For (n=1; N<=t; N++)
{
M=n/(2 * n + 1);
Sum=sum + m;
}
Return (sum * 2);
}

CodePudding user response:

Not sure, you bring n=2, in just can't see yao
Under the condition of n=2, formula is 1/3 * 2/5
You this loop was added in the sum inside a 2/5, by analogy, behind every item does not conform to the

CodePudding user response:

Don't meet; 1/3 * 2/5 this multiplication is not reflected. In addition, the value of t need to do a qualified, not these values are 1, 2,

Search on the net, look at other people's logic, consult ~

CodePudding user response:

Yes, also need some supplement, rigorous

CodePudding user response:

I think, according to the program's original intention, t should be PI calculation accuracy, as a double incoming, not as judge of the loop condition,