I try to use malloc to create a string, and then assignment, but failed, is this why? There is not even an error,

 
#include  
#include  

Int main () {
Char * a=(char *) malloc (5 * sizeof (char)); 
Char * b=a; 
for(int i=0; i<5; I++) {
* (b++)='1'; 
} 
Printf (" % s \ n ", a); 
} 

CodePudding user response:

 
Printf (" % s \ n ", a); 

CodePudding user response:

C string to end with a '\ 0',
The following code for reference

 
#include  
#include  
# define N 5 
Int main () 
{
Char * a=(char *) malloc ((N + 1) * sizeof (char)); 
int i; 
For (I=0; i{
* (a + I)='1'. 
} 
* (a + I)='\ 0'; 
Printf (" % s \ n ", a); 
return 0 ; 
} 

CodePudding user response:

And the lack of the terminator

CodePudding user response:

reference 1st floor flying_music response:

 
Printf (" % s \ n ", a); 

Didn't end with a '\ 0', it is not a string.