CodePudding user response:

This function take steps
One is to calculate the number of each each, can use % 10 to get
Then add each cubic want to determine whether is equal to the number of
Then put these steps into a cycle, the cycle running from 100 to 1000,

CodePudding user response:

Reference:

 # include 

Int * calc (int result [], int the begin=100, int the end=1000). 

Int main () 
{
Int result [10]={0}, * a; 
A=calc (result); 
for (int i=0; i<10; I++) 
If (a [I]!=0) 
Printf (" % d ", a [I]); 

return 0; 
} 

Int * calc (int result [], int the begin, int the end) 
{
Int I, n, temp, sum, k=0; 
For (I=begin; iTemp=I; sum=0; 
While (temp) {
N=temp % 10; 
The sum +=n * n * n. 
Temp/=10; 
} 
If (sum==I) result [k++]=I; 
} 
return result; 
}