title
String concatenation, connect "acegikm" and "BDFHJLNPQ"

code

 # include & lt; Stdio. H> 

20 # define N 
Char arr [N]={0}; 

Void main () 
{
Char a []="acegikm"; 
Char [b]="BDFHJNPQ"; 
int i=0; 
for(i=0; i <7. I++) 
Arr=[I] a [I]; 
for(i=0; i <9. I++) 
Arr [I + 7] [I]=b; 
for(i=0; i Printf (" % c \ n ", arr [I]); 
} 

Results the



The arithmetic idea for the
If you want to any string to connect, can use a two-dimensional array of target string, then two-dimensional arrays into one array is implemented any string concatenation

code

//connection 
Void Connect (char [M] [N], a char * b) 
{
int i,j; 
int k=0; 
//will be a [M] [N] elements, in turn, assign a value to the array b 
for(i=0; ifor(j=0; A [I] [j].='\ 0'; J++) 
B=[k++] a [I] [j];//use Pointers for * (* (a + I) + j) 
B [k]='\ 0'; 
} 

CodePudding user response:

 # include & lt; Stdio. H> 

20 # define N 
Char arr [N]={0}; 

Int main () 
{
Char a []="acegikm"; 
Char [b]="BDFHJNPQ"; 
int i=0; 
for(i=0; i Arr=[I] a [I]; 
for(i=0; i Arr [I + 7] [I]=b; 
# if 0 
for(i=0; i Printf (" % c \ n ", arr [I]); 
# the else 

Puts (arr); 
# endif 
} 

For your reference ~

CodePudding user response:

 char ch; 
int i=0; 

Cha r * p=a; 
While (ch=* p++) 
Arr [i++]=ch; 

P=b; 
While (ch=* p++) 
Arr [i++]=ch; 

Arr [I]='\ 0';