Program: enter a 3 line 4 column element value of two dimensional array, a custom function called for the lowest value of two dimensional array element of each column and the value of output and value by returning back to the main function,
Such as: input array is:
1 2 3 4
0 8 3 1
3, 5, 7 1
Output: 6

CodePudding user response:

Address code: just use a double loop type, a double cycle comparison and accumulation, specific as follows

 
#include  
using namespace std; 
Int the sum (int (* ar) [4]) {
Int all=0; 
Int var. 
int i, j; 
for (i=0; i <4. + + I) {
Var=ar [0] [I]; 
For (j=1; J & lt; 3; + + j) 
{
If (var & gt; Ar [j] [I]) 
Var=ar [j] [I]; 
} 
All +=var. 
} 
Return all; 
} 
Int main () 
{
int i, j; 
Int ar [3] [4]; 
for (i=0; i <3; + + I) 
For (j=0; J & lt; 4. + + j) 
Cin & gt;> Ar [I] [j]; 
Cout & lt; return 0; 
} 

CodePudding user response:

Upstairs is a c + +, translated into c

 
# define _CRT_SECURE_NO_WARNINGS 
#include  
#include  

Int mArray (int myArr [] [4]) 
{
Int I=0, j=0, min=0, sum=0; 
for (i=0; i <4. I++) 
{
Min=myArr [0] [I]; 
For (j=0; J & lt; 3; J++) 
{
If (min & gt; MyArr [j] [I]) 
{
Min=myArr [j] [I]; 
} 
} 
The sum +=min; 
} 
return sum; 
} 

Int main (void) 
{
Int arr [3] [4]={0}; 
Int I=0, j=0, sum=0; 

Printf (" input array elements: \ n "); 
for (i=0; i <3; I + +) 
{
For (j=0; J & lt; 4. J++) 
{
The scanf (" % d ", & amp; Arr [I] [j]); 
} 
} 

Sum=mArray (arr); 
Printf (" % d \ n ", sum); 

getchar(); 
return 0; 
} 

CodePudding user response:

Upstairs is right,
Int mArray (int myArr [] [4])
{
Int I=0, j=0, min=0, sum=0;
for (i=0; i <4. I++)
{
Min=myArr [0] [I];
For (j=0; J & lt; 3; J++)
{
If (min & gt; MyArr [j] [I])
{
Min=myArr [j] [I];
}
}
The sum +=min;
}
return sum;
} of this paragraph is the topic request you
A variable name can be set