Known sinx approximate computation formula is as follows:

Sin x=x - 3 x3/! + x5/5! - 7 x7/! +... X2n + (1) n - 1-1/(2 n - 1)!

Where x as the radian, n positive integers, write programs based on user input x and n value, using the approximate calculation formula of the sinx approximation, the required output 8-bit decimal,

[form] input

From the console input decimal x (0 & lt;=x<=20) and an integer n (1 & lt;=n<=5000), two Numbers separated by a space,

[] output form

Results: the console output formula 8-bit decimal,

[1] sample input

0.5236 4
[1] sample output

0.50000105
[sample input 2]

0.5236 50
[2] sample output

0.50000106
[example]

Input x 0.5236, n is 4, sinx approximate calculation formula of the value of 0.50000105, 8-bit decimal; Also, input x 0.5236, n is 50, approximate calculation formula of sinx values, a value of 0.50000106, 8-bit decimal,

Note: in order to ensure the accuracy of the data and consistency, please use the double data type save calculation results,

CodePudding user response:

Reference:

 # include 
# include 

Double fac (int n); 
Double sinx (double radian, int n); 

Int main (int arg c, char * argv []) 
{
Double radian; 
Int n; 
Lf the scanf (" % % d ", & amp; Radian, & amp; N); 
Printf (" %. 8 f \ n ", sinx (radian, n)); 

return 0; 
} 


Double fac (int n) 
{
Double num=1; 
for(int j=1; J<=n; J++) 
Num=num * j; 
Return num. 
} 

Double sinx (double radian, int n) 
{
Double x=radian; 
Int I=2 and k=0, j=1; 
Double temp, result=0.0; 
Do {
K=2 * j - 1; 
Temp (1, I) *=pow pow (x, k)/fac (k); 
Result=result + temp; 
i++; 
J++; 
} while (j<=n); 
return result; 
}