Please help take a look at the C language-CodePudding

Thank you thank you greatly,

CodePudding user response:

 
Int a=0, aa=0, aaa=0; 
While (1) 
{
Cin> a; 
if(! A) break; 
if(! (a % 2)) + + aa, aaa +=a; 
} 
Cout

CodePudding user response:

 void sum_even (void) 
{
Int num, CNT=0, sum=0; 


While (the scanf (" % d ", & amp; Num) & amp; & Num) {
If (num & gt; 0 {
Cnt++; 
The sum +=CNT; 
} 
} 

Printf (" sum=% d \ n ", sum); 
}

For your reference ~

CodePudding user response:

The scanf=& gt; Cin
Printf=& gt; cout

CodePudding user response:

reference 2 building self-confidence boy reply:

 void sum_even (void) 
{
Int num, CNT=0, sum=0; 


While (the scanf (" % d ", & amp; Num) & amp; & Num) {
If (num & gt; 0 {
Cnt++; 
The sum +=CNT; 
} 
} 

Printf (" sum=% d \ n ", sum); 
}

For reference ~

Can't say, run out??

CodePudding user response:

reference 1/f, the wise know already should good karma response:

 
Int a=0, aa=0, aaa=0; 
While (1) 
{
Cin> a; 
if(! A) break; 
if(! (a % 2)) + + aa, aaa +=a; 
} 
Cout

The whole don't come out aye??

CodePudding user response:

Reference:

 # include 

Int main () 
{
Int ecnt=0, esum=0, n, PCNT=0, psum=0; 
While (the scanf (" % d ", & amp; N)==1 & amp; & n!=0) {
If (n % 2==0) {//even 
Ecnt++; 
Esum +=n; 
} 
If (n> 0) {//positive 
Pcnt++; 
Psum +=n; 
} 

} 
Printf (" ecnt=% d, esum=% d \ n ", ecnt, esum);//even accumulative number and and 
Printf (" PCNT=% d, psum=% d \ n ", PCNT and psum);//positive accumulative number and and 

return 0; 
}

CodePudding user response:

reference 4 floor wood ooze ooze response:

Quote: refer to the second floor confident boy reply:

void sum_even (void)
{
Int num, CNT=0, sum=0;

While (the scanf (" % d ", & amp; Num) & amp; & Num) {
If (num & gt; 0 {
Cnt++;
The sum +=CNT;
}
}

Printf (" sum=% d \ n ", sum);
}

For reference ~

Can't say, run out?

Don't come out what is the second right?
On the basis of this change, you have hands have a brain, can't change yourself?

CodePudding user response:

 

Int a=0, aa=0, aaa=0; 
While (1) 
{
STD: : cin> a; 
if(! A) break; 
if(! (a % 2)) + + aa, aaa +=a; 
} 
STD: : cout

Cin> a;==the scanf (" % d ", & amp; A)
Cout CodePudding user response:

 
Int a=0, aa=0, aaa=0; 

















While (1) 
{

















STD: : cin> a; 

















if(! A) break; 

















If (a> Aa, aaa +=0) + + a; 
} 




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