Result is right, but always said after running period of mistake, I really don't know where is-CodePudding

CodePudding user response:

At first glance, the input should be changed like this:

 while ((a) [j]=getchar ())! )='\ n' {
j++; 
}

CodePudding user response:

Modified as follows, for your reference:

 # include 

Int main () 
{
Int I, j, n, m; 
Char a [1024], w; 
J=0; 
The scanf (" % d ", & amp; N); 
getchar(); 
While ((a) [j]=getchar ())! )='\ n' {
j++; 
} 
for(i=1; i<=n; I++) {
For (m=1, j w=a, [m]. M> 0; M -) {
A [m]=a [m - 1); 
} 
A [m]=w; 
} 
for(i=0; iPrintf (" % c ", a [I]); 
} 

return 0; 
}

CodePudding user response:

Fixed upstairs, line 22 increase printf (" \ n "); :

 # include 

Int main () 
{
Int I, j, n, m; 
Char a [1024], w; 
J=0; 
The scanf (" % d ", & amp; N); 
getchar(); 
While ((a) [j]=getchar ())! )='\ n' {
j++; 
} 
for(i=1; i<=n; I++) {
For (m=1, j w=a, [m]. M> 0; M -) {
A [m]=a [m - 1); 
} 
A [m]=w; 
} 
for(i=0; iPrintf (" % c ", a [I]); 
} 
printf("\n"); 

return 0; 
}

CodePudding user response:

reference QZJHJXJ reply: 3/f

corrections upstairs, line 22 increase printf (" \ n "); :

 # include 

Int main () 
{
Int I, j, n, m; 
Char a [1024], w; 
J=0; 
The scanf (" % d ", & amp; N); 
getchar(); 
While ((a) [j]=getchar ())! )='\ n' {
j++; 
} 
for(i=1; i<=n; I++) {
For (m=1, j w=a, [m]. M> 0; M -) {
A [m]=a [m - 1); 
} 
A [m]=w; 
} 
for(i=0; iPrintf (" % c ", a [I]); 
} 
printf("\n"); 

return 0; 
}

Well, if not, good mentality collapsed, difficult

CodePudding user response:

What kind of error?

CodePudding user response:

Try to change this:

 # include 
#include 
Int main () 
{
Int I, len, n, m; 
Char a [1001], w; 
The scanf (" % d ", & amp; N); 
getchar(); 
Gets (a); 
Len=strlen (a); 
for(i=1; i<=n; I++) {
For (m=, len - 1 w=a, [m]. M> 0; M -) {
A [m]=a [m - 1); 
} 
A [m]=w; 
} 
Puts (a); 

return 0; 
}

CodePudding user response:

 
# include & lt; stdio.h> 
#include 
Int main (int arg c, char * argv []) 
{
Int I, len, n, k; 
Char STR [1001], [1001] s. 
{

The scanf (" % d % s ", & amp; N, STR); 
Len=strlen (STR); 
K=n % len;//& gt;=the movement of the len are repeated 
/* subject required is a circular movement, if the string end to end, is the starting point to the location of the mobile, as a string, before and after boundary exchange can be realized for k */
Strncpy (s, STR + len - k, k); 
Strncpy (s + k, STR, len - k); 
S [len]='\ 0'; 
Printf (" % s \ n ", s); 
} 
return 0 ; 
}