{
int i=0;
While (WSTR [I]!=0)
{
If (WSTR [I] & amp; 0 x80)
{
return true;
}
i++;
}
return false;
}//this method intelligent judge the Chinese characters
CodePudding user response:
http://www.unicode.orgCodePudding user response:
Baidu once isascii () to see is that ok