Requirements:
2 read integer (5 points)
Subject content:
Your program to read an integer range is (000-100000100), then use Chinese pinyin to the integer each output,
1234 as input, output:
Yi er SAN si
Note that there is a space between the pinyin of each word, but in the end there is no space behind the words that, when faced with a negative number in the output at the beginning of the "fu", such as - 2341 output for:
Fu er SAN si yi
Input format:
An integer, the range is (000-100000100),
The output format:
Said every digits of the integer hanyu pinyin, each digit of pinyin are separated by Spaces, no Spaces at the end,
Input the sample:
- 30
The output sample:
Fu SAN ling
Time limit: 500 ms memory limit: 32000 KB

Code:

 # include & lt; stdio.h> 

Int place_value (int n) 
{
Int j=1; 
for (int i=1; I & lt; n; I++) 
{
J *=10; 
} 
Return j; 
} 

Int main (void) 
{
Int n, I, j=0, t, m; 

The scanf (" % d ", & amp; n); 

If (n & lt; 0) 
{
Printf (" fu "); 
N=n - n * 2; 
} 
M=n; 
Do 
{
M/=10; 
j++; 
} while (m & gt; 0); 
For (; J & gt; 0; J -) 
{
T=n/place_value (j); 
The switch (t) 
{
Case 0: 
Printf (" ling "); 
break; 
Case 1: 
Printf (" yi "); 
break; 
Case 2: 
Printf (" er "); 
break; 
Case 3: 
Printf (" SAN "); 
break; 
Case 4: 
Printf (" si "); 
break; 
Case 5: 
Printf (" wu "); 
break; 
Case 6: 
Printf (" liu "); 
break; 
Case 7: 
Printf (" qi "); 
break; 
Case 8: 
Printf (" ba "); 
break; 
Case 9: 
Printf (" jiu "); 
break; 
Default: 
break; 
} 
If (place_value (j) & gt; 1) 
printf(" "); 
N=n - t * place_value (j); 
} 

return 0; 
} 

Code is to China university mooc upload above, why line sixty-eight, please write to: if (n & gt; 9), submitted a case shows that the output format is wrong?