Introduction to C-CodePudding

Judge a number n can be divided exactly by 3 and 5 at the same time:

 # include 
Int main () {
int n; 
Printf (" please enter a number: "); 
The scanf (" % d ", & amp; N); 
If (n % 3==0 & amp; & N % 5==0) {
Printf (" % d can also be divided exactly by 3 and 5 ", n); 
} 
The else {
Printf (" % d cannot be divided exactly by 3 and 5 "at the same time, n); 
} 
return 0; 
}

Two idA, B are respectively 2, 3, 2, 3 first swaps to B, A:

 # include 
Int main () {
Int A=2; 
Int B=3; 
Int C; 
C=B; 
B=A; 
A=C. 
Printf (" A=% d, B=% d ", A, B); 
return 0; 
}

The prime number between 100-200 output:

 # include 
Int main () {
int n=0; 
For (n=100; N & lt;=200; N++) {
int i=0; 
For (I=2; I & lt;=n - 1; I++) {
If I==0) (n % {
break; 
} 
} 
If (I & gt;=n) {
Printf (" % d \ n ", n); 
} 
} 
return 0; 
}

Number 3 a, b, c, demand and output them in size order:

 # include 
Int main () {
Int a, b, c, n; 
Printf (" please enter the number 3: "); 
The scanf (" % d, % d, % d ", & amp; A, & amp; B, & amp; C); 

If (a & lt; B) {
N=b; B=a; A=n; 
} 
If (a & lt; C) {
N=c; c=a; A=n; 
} 
If (b & lt; C) {
N=c; C=b; B=n; 
} 
Printf (" % d, % d, % d ", a, b, c); 

return 0; 
}

In turn 10 number input, that output the largest number:

 # include 
Int main () {
int i; 
Int num [10]. 
Int Max; 
Printf (" please enter the number 10: "); 
for(i=0; I & lt; 10; I++) 
The scanf (" % d ", & amp; Num [I]); 
For (I=0, Max num=[0]. I & lt; 10; I++) 
Max num=[I] & gt; Max? Num [I] : Max; 
Printf (" Max=% d \ n ", Max). 
return 0; 
}

For 1 + 2 + 3 +... + 100:

 # include 
Int main () {
int i; 
int sum=0; 
for(i=0; I & lt;=100; + + I) {
Sum=sum + I; 
} 
printf("sum=%d",sum); 
return 0; 
}

CodePudding user response:

 # include 
Int main () {
int n=0; 
For (n=100; N & lt;=200; N++) {
int i=0; 
For (I=2; I * I & lt; n; I++) {
If I==0) (n % {
break; 
} 
} 
If (I & gt;=n) {
Printf (" % d \ n ", n); 
} 
} 
return 0; 
}

For your reference ~

 # include 
Int main () {
int i; 
Int num [10]. 
Int Max; 
Printf (" please enter the number 10: "); 
for(i=0; I & lt; 10; I++) 
The scanf (" % d ", & amp; Num [I]); 
For (I=1, Max num=[0]. I & lt; 10; I++)//I starting from 1 
If (Max & lt; Num [I]) 
Max num=[I]; 
//Max num=[I] & gt; Max? Num [I] : Max; 
Printf (" Max=% d \ n ", Max). 
return 0; 
}

For your reference ~