E approximation, e material 1 + 1/1! + 1/2! + a third! +... + 1/n! Calculating various kinds of, until the last item value is less than 10 (4) (calculation items are greater than or equal to 10 (4))

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Reference:

 # include 

Double fun_e () 
{
Double sum=1;//first set to 1 
Double temp=1; 
int i=1; 
While (temp> E=1-4) {//the last item value is less than 10 (4) 
Temp=temp/I;//the second 1/1, namely 1/1! ; 1/2, the third is 1/2. ; Item 4 (1/2)/3, namely a third! . 
Sum=sum + temp;//[sum=1 + 1/1 + 1/2! + 1/3! + 1/4!! + 1/5 +... + 1/n!] 
i++; 
} 
return sum;//return the sum 
} 

Int main () 
{
Double e=fun_e (); 
Printf (" e=% lf \ n ", e); 

return 0; 
}