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//program content is to realize the palindrome judgment: 

//there's just one problem: 
//in order to store the input digital number on every one, I defined in the program with a capacity of 9999 array, how to implement according to the input digital 
//digits to define an array of capacity?? 


#include  

Int main () 
{//problem a: 
Int b [10].//C int scope is: in 2147483648 ~ 2147483647, the largest decimal is 10 digits, so b [?] Not so much 

Int a, n=0, I=0, j=0, c; 
Printf (" please enter a number \ n "); 
The scanf (" % d ", & amp; A); 
C=a; 
//if here to join the definition of dynamic array, the foremost int b [10]; Definition to delete or add '//' instead of the head annotation 
//based on the input number of digits to define an array capacity: first you need to calculate the input number of digits of n, 
//then: int * b=(int *) malloc (sizeof (int) * n); Memset (b, 0, sizeof (int) * n); 

For (a=c; A>=10; A=a/10) 
{
[I] b=a % 10; 
i=i+1; 
} 
[I] b=a % 10; 
If (I % 2==1) 
{
For (n=0; N<(I + 1)/2; N++) 
{
If (b [n]==b [I - n]) 
{
J=j + 1; 
} 
} 
If (j==(I + 1)/2) 
Printf (" True "); 
The else 
Printf (" False "); 
} 
The else 
{
For (n=0; N<=I/2; N++) 
{
If (b [n]==b [I - n]) 
{
J=j + 1; 
} 
} 
If (j==I/2 + 1) 
Printf (" True "); 
The else 
Printf (" False "); 
} 
//if you define [b] is dynamic, and at the end of the code statement before input: free (b); Explicitly release the array, or without=implicit release, 

return 0; 
} 


//the problem 2: 
//error: a redefinition of 'main' compiler error, repeat the definition of the main 
//this question bank operation method is: you just need to make up for all the lack of code 

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