The letters in the string is replaced by a letter after in the alphabet, will be converted to uppercase lowercase letters at the same time, such as input: ABCD, output: bcde

CodePudding user response:

Title is not clear, and Z Z how to deal with didn't say, here in Zz turn a processing

 
#include  
#include  

Int main () {
Char * p, STR []="asdfaGSFGSDFGZFADzsadf"; 
Printf (" % s \ n ", STR); 
P=STR. 
While (* p) 
{
If (* p=='z' | | * p=='z') 
* p='a'; 
Else if (* p & gt;='A' & amp; & * p & lt; 'Z') 
+ (* p * p='a' - 'a') + 1; 
The else 
* p +=1; 
p++; 
} 
Printf (" % s ", STR); 

return 0; 
} 

CodePudding user response:

According to the topic, will be converted to uppercase lowercase letters at the same time, which in turn is at the same time converts uppercase to lowercase, should understand, so it's sample explain impassability, for reference:

//the current replacement string of letters in the alphabet after a letter, will be converted to uppercase lowercase letters at the same time, 
//as input, the ABCD, output: bcde 

# include 

Void str_Cap_Low (char * s); 

Int main () 
{
Char STR [256]. 
gets(str); 
Str_Cap_Low (STR); 
Puts (STR); 

return 0; 
} 

Void str_Cap_Low (char * s) 
{
While (* s) {
If ((* s & gt;='a' & amp; & * s & lt; )='z') {
If (* s=='z') 
* s='a'; 
The else 
* s +=1; 
* s -=32; 
} the else 
If ((* s & gt;='A' & amp; & * s & lt; )='Z') {
If (* s=='Z') 
* s='A'; 
The else 
* s +=1; 
* s +=32; 
} 
s++; 
} 
} 

CodePudding user response:

#include
Int main (int arg c, char * argv [])
{
Char STR [100], * p=STR;

The scanf (" % s ", STR);
While (* p)
{
//((* p=(* p | 0 x20) + 1) & lt;='z') | | (* p='a');//lowercase
//* p=((* p | 0 x20) + 1 - 'a') % 26 + 'a';//lowercase
//* p=(* p & amp; 0 XDF) + 1 - 'A') % 26 + 'A';//capital

((* p=(* p & amp; 0 XDF) + 1) & lt;='Z') | | (* p='A');//capital
P++;
}
Printf (" % s \ n ", STR);
Return 0;
}