O equation ax + bx + c ^ 2=0 roots, there are two different real root, there are two equal real root

 # include 
#include 
Int main () {
Int a, b, c; 
Printf (" please input a, b, c: "); 
The scanf (" % d, % d, % d ", & amp; A, & amp; B, & amp; C); 
Float m, n; 
Int d=b * b - (4 * a * c); 
If (d & gt; 0 {
B + m=((1) * SQRT (d))/(2 * a); 
N=((1) * b - SQRT (d))/(2 * a); 
Printf (" there are two is not equal to the real root of m=% f, n=% f ", m, n); 
{} else if (d==0) 
M=(1)/(2 * a) * b; 
N=(1)/(2 * a) * b; 
Printf (" have two equal real root of m=% f, n=% f ", m, n); 
} else {
Printf (" there is no real root!" ); 
} 
return 0; 
} 

The output is a leap year year 1900-2000 years, but it can't be divided exactly by 100 can be divided exactly by 4, divisible by 400

 # include 
Int main () {
Int year; 
For (year=1900; Year & lt;=2000; Year++) {
If (year % 4==0 & amp; & Year % 100!=0 | | year %==0 400) 
Printf (" % d is a leap year \ n ", year); 
The else 
Printf (" % d is not a leap year \ n ", year); 
} 
return 0; 
} 

Find the greatest common divisor of m and n two

 # include 
Int main () {
Int m, n, r; 
Printf (" please enter the number two: "); 
The scanf (" % d, % d ", & amp; M, & amp; n); 

While (n!=0) {
R=m % n; 
M=n; 
N=r; 
} 
Printf (" the greatest common divisor of the number two is: % d \ n ", m); 
return 0; 
} 

Input the number 10, output is one of the biggest number

 # include 
Int main () {
Int n [10]. 
int i; 
Int Max=n [0]; 
Printf (" please enter the number 10: "); 
for(int i=0; i <=10; + + I) 
The scanf (" % d ", & amp; N [I]); 
for(int i=0; i <=10; + + I) 
Max=n [I] & gt; Max? N [I] : Max; 
Printf (" Max=% d \ n ", Max). 
return 0; 
} 

CodePudding user response:

 if (year % 4==0 & amp; & Year % 100!=0 | | year %==0 400) 

This change:

 if ((year % 4==0 & amp; & Year % 100!=0) | | year %==0 400) 

Some logic clearer ~

 # include 
Int main () {
Int n [10]. 
//int I; 
//int Max=n [0];//random values, which may be Max also can not let go of random values 
Int Max; 
Printf (" please enter the number 10: "); 
for(int i=0; i <=10; + + I) 
The scanf (" % d ", & amp; N [I]); 
Max=n [0];//in this initialization 
for(int i=0; i <=10; + + I) 
Max=n [I] & gt; Max? N [I] : Max; 
Printf (" Max=% d \ n ", Max). 
return 0; 
} 

For your reference

Max initialization has a problem, may lead to abnormal results program;

CodePudding user response:

The

reference

# include
Int main () {
Int n [10].
int i;
Int Max=n [0];
Printf (" please enter the number 10: ");
for(int i=0; i <=10; + + I)
The scanf (" % d ", & amp; N [I]);
for(int i=0; i <=10; + + I)
Max=n [I] & gt; Max? N [I] : Max;
Printf (" Max=% d \ n ", Max).
return 0;
}

For () in an array subscript cross-border operation, should be changed to: the for (int I=0; i<10; i++)

CodePudding user response:

Ok, thank you