For a string is
String a="123124125";
To turn him into an array [123124125] to do?

CodePudding user response:

The substring intercept string

CodePudding user response:

Reference:

 # include 
# include 

using namespace std; 

Int main () 
{
Int b [10]={0}, j=0, I=0; 
String a="1234124 5125126127,12,1"; 
While (a [I]) {
If (a [I]! )=', '
B=b [j] [j] * 10 + a, [I] - '0'. 
The else j++; 
i++; 
} 
for(i=0; I<=j; I++) 
Printf (" % d, b [I]); 

return 0; 
} 

CodePudding user response:

Fyi:

 # include & lt; Stdio. H> 
Char [] s="123 ab 4"; 
Char * p; 
Int n, n, k; 
Void main () {
P=s; 
While (1) {
K=sscanf (p, "% d % n, & amp; V, & amp; N); 
Printf (" k, v, n=% d, % d, % d \ n ", k, v, n); 
If (1)==k {
P +=n; 
{} else if (0==k) 
Printf (" skip char [c] % \ n ", p [0]). 
P++; 
} else {//EOF==k 
break; 
} 
} 
Printf (" End. \ n "); 
} 
//k, v, n=1123, 
//k, v, n=0123, 
//the skip char [] 
//k, v, n=0123, 
//the skip char [a] 
//k, v, n=0123, 
//the skip char [b] 
//k, v, n=1,4,2 
//k, v, n=1,4,2 
//End. 

CodePudding user response:

Two methods, a short answer the boost library function of boost: : the split, another kind is to write their own

Want to learn can direct messages to me

CodePudding user response:

Miss zhao, the method of combining # 3 floor for reference:

 # include & lt; Stdio. H> 
Int main () 
{
Char [] s="1234124 5125126127,12,1"; 
Char * p; 
Int n, n, k, I=0, b [10]={0}; 
P=s; 
While (1) {
K=sscanf (p, "% d % n, & amp; V, & amp; N); 
If (1)==k {
B [i++]=v; 
P +=n; 
{} else if (0==k) 
P++; 
} else {//EOF==k 
break; 
} 
} 
for(int j=0; JPrintf (" % d, b [j]); 

return 0; 
}