From big to small, why my result is wrong-CodePudding

#include
Void main ()
{
15,34,6,27,48,4,20 int a [7]={}, I, j, k, t;
Printf (" before sorting sequence: ");
for(i=0; i<7. I++)
Printf (" % 5 d, "a [I]);
for(i=0; i<7. I++)
{k=I;
for(j=i+1; J<7. J++)
If (a [j] & gt; A [k]) k=j;
if(k!=I) t=a, [k]. a[k]=a[i]; A [I]=t; }
Printf (" \ n from big to small sorted (select) \ n ");
for(i=0; i<7. I++)
Printf (" % 5 d, "a [I]);
printf("\n");
}

CodePudding user response:

Modified as follows, for reference:

 # include 
Void main () 
{
15,34,6,27,48,4,20 int a [7]={}, I, j, k, t; 
Printf (" before sorting sequence: "); 
for(i=0; i<7. I++) 
Printf (" % 5 d, "a [I]); 
for(i=0; i<7-1; I++) 
{
k=i; 
for(j=i+1; J<7. J++) 
If (a [j] & gt; A [k]) k=j; 
if(k!=I) 
{
T=a, [k]. 
a[k]=a[i]; 
A [I]=t; 
} 
} 
Printf (" \ n from big to small sorted (select) \ n "); 
for(i=0; i<7. I++) 
Printf (" % 5 d, "a [I]); 
printf("\n"); 

}

CodePudding user response:

 # include 


//void main () 
Int main () 
{
15,34,6,27,48,4,20 int a [7]={}, I, j, k, t; 
Printf (" before sorting sequence: "); 
for(i=0; i<7. I++) 
Printf (" % 5 d, "a [I]); 
for(i=0; i<7. I++) 
{
k=i; 
for(j=i+1; J<7. J++) 
If (a [j] & gt; A [k]) 
K=j; 
# if 0 
if(k! I)={
T=a, [k]. a[k]=a[i]; A [I]=t; 
} 
# the else 
If (k!=j) 
T=a [k], a [k]=[I], a [I]=t; 
# endif 
} 
Printf (" \ n from big to small sorted (select) \ n "); 
for(i=0; i<7. I++) 
Printf (" % 5 d, "a [I]); 

printf("\n"); 

return 0; 
}

For your reference ~

A little curly braces, or by a comma instead of a semicolon;

CodePudding user response:

You of the inner for loop in the second if part of an exchange of the three statements with curly braces, it is a whole

if(k! I)={
T=a, [k]. a[k]=a[i]; A [I]=t;
}

CodePudding user response:

reference 2 building self-confidence boy reply:

 # include 


//void main () 
Int main () 
{
15,34,6,27,48,4,20 int a [7]={}, I, j, k, t; 
Printf (" before sorting sequence: "); 
for(i=0; i<7. I++) 
Printf (" % 5 d, "a [I]); 
for(i=0; i<7. I++) 
{
k=i; 
for(j=i+1; J<7. J++) 
If (a [j] & gt; A [k]) 
K=j; 
# if 0 
if(k! I)={
T=a, [k]. a[k]=a[i]; A [I]=t; 
} 
# the else 
If (k!=j) 
T=a [k], a [k]=[I], a [I]=t; 
# endif 
} 
Printf (" \ n from big to small sorted (select) \ n "); 
for(i=0; i<7. I++) 
Printf (" % 5 d, "a [I]); 

printf("\n"); 

return 0; 
}

For your reference ~

A little curly braces, or by a comma instead of a semicolon;

The if (k!=j) into the if (k!=I) because the initial k=I;

CodePudding user response:

If (k!=I)

reference

without braces

 
For (I=0; i <7. I++) 
{
K=I; 
For (j=I + 1; J & lt; 7. J++) 
If (a [j] & gt; A [k]) 
k=j; 
If (k!=I) 
{
T=a, [k]. 
A [k]=a, [I]. 
A [I]=t; 
} 
}