O four natural Numbers a, b, c, d (a<=b<=c<=d), makes the following equation was established: 1/a + 1 + 1/+ 1 b/c/d=1
Using C language to complete, thank you

CodePudding user response:

 float a=4, b=4, c=4, d=4; 

Finish the manual

CodePudding user response:

 # include & lt; stdio.h> 
#include  
#include  

Int main (void) 
{
Int I, j, k, z; 
Float x; 

For (I=1; ; I++) 
For (j=1; J & lt;=I; J++) 
For (k=1; K & lt;=j; K++) 
For (z=1; Z & lt;=k; Z++) {
X=1.0/I/j/k + 1.0 + 1.0 + 1.0)/z; 

If (fabsf (x - 1) & lt; 1-6 e) {
Printf (" % d, % d, % d, % d \ n ", I, j, k, z); 
Printf (" % 2 f + %. 2 f + %. 2 f + %. 2 f=%. 2 f \ n ", 1.0/I/j, 1.0 1.0/k, 1.0/z, x); 
sleep(1); 
//return 0; 
} 
} 

return 0; 
} 

For your reference ~

The output of the sleep need to wait for one ~

CodePudding user response:

thank you

CodePudding user response:

This is what ah
crying

CodePudding user response:

reference 4 floor qq_57019597 response:

This is what ah
Crying

The header file: under Windows - & gt; Windows. J h, Sleep is a case-sensitive, some compilers are capitalized, have a plenty of lowercase,

Line 2: # include Row 19: Sleep (1);
Line 16, the if (fabs) (x - 1 & lt; 1-6 e) {