I ask, why all my sprintf conversion when data type double to 0?-CodePudding

The code is as follows:
Char tmpbuffer [20].
Double U13Coef [8]={0.000000428344451, 0.000041556454936, 0.001508777414466, 0.02414235618335, 0.158289852824976, 1.54926741892562, 0.162671275351189, 0.55};
for (i=0; i<8; I++)
{
Sprintf (tmpbuffer, "% f", U13Coef [I]);
}
The output is always 0.000000; Don't understand, float type can output;

CodePudding user response:

 # include & lt; stdio.h> 
Int main () {
Char tmpbuffer [20]. 
Double U13Coef [8]={0.000000428344451, 0.000041556454936, 0.001508777414466, 0.02414235618335, 0.158289852824976, 1.54926741892562, 0.162671275351189, 0.55}; 
for (int i=0; i<8; I++) {
Sprintf (tmpbuffer, "%. 15 lg," U13Coef [I]); 
Printf (" I: % d tmpbuffer:] [% s \ n ", I, tmpbuffer); 
} 
return 0; 
} 
//I: 0 tmpbuffer: [4.28344451 e-07] 
//I: 1 tmpbuffer: [4.1556454936 e-05] 
//I: 2 tmpbuffer: [0.001508777414466] 
//I: 3 tmpbuffer: [0.02414235618335] 
//I: 4 tmpbuffer: [0.158289852824976] 
//I: 5 tmpbuffer: [1.54926741892562] 
//I: 6 tmpbuffer: [0.162671275351189] 
//I: 7 tmpbuffer: [0.55] 
//

CodePudding user response:

 # include & lt; stdio.h> 
Int main () {
Char tmpbuffer [20]. 
Double U13Coef [8]={0.000000428344451, 0.000041556454936, 0.001508777414466, 0.02414235618335, 0.158289852824976, 1.54926741892562, 0.162671275351189, 0.55}; 
for (int i=0; i<8; I++) {
Sprintf (tmpbuffer, "%. 15 lf U13Coef [I]); 
Printf (" I: % d tmpbuffer:] [% s \ n ", I, tmpbuffer); 
} 
return 0; 
} 
//I: 0 tmpbuffer: [0.000000428344451] 
//I: 1 tmpbuffer: [0.000041556454936] 
//I: 2 tmpbuffer: [0.001508777414466] 
//I: 3 tmpbuffer: [0.024142356183350] 
//I: 4 tmpbuffer: [0.158289852824976] 
//I: 5 tmpbuffer: [1.549267418925620] 
//I: 6 tmpbuffer: [0.162671275351189] 
//I: 7 tmpbuffer: [0.550000000000000] 
//

CodePudding user response:

Such a change, for your reference:

 # include 
Int main () 
{
Int I; 
Char tmpbuffer [8] [20]. 
Double U13Coef [8]={0.000000428344451, 0.000041556454936, 0.001508777414466, 0.02414235618335, 
0.158289852824976, 1.54926741892562, 0.162671275351189, 0.55}; 
for (i=0; i<8; I++) 
{
Sprintf (tmpbuffer [I], "% 18.15 f," U13Coef [I]); 
Printf (" % s \ n ", tmpbuffer [I]); 
} 

return 0; 
} 


//0.000000428344451 
//0.000041556454936 
//0.001508777414466 
//0.024142356183350 
//0.158289852824976 
//1.549267418925620 
//0.162671275351189 
//0.550000000000000 
//please press any key to continue...

CodePudding user response:

 # include & lt; stdio.h> 

Int main (void) 
{
int i; 
//char tmpbuffer [20]. 
Char tmpbuffer [64]. 
Double U13Coef [8]={0.000000428344451, 0.000041556454936, 0.001508777414466, 0.02414235618335, 0.158289852824976, 1.54926741892562, 0.162671275351189, 0.55}; 

for (i=0; i<8; I++) {
Sprintf (tmpbuffer, "%. 15 lf U13Coef [I]); 
Puts (tmpbuffer); 
} 
return 0; 
}

For your reference ~
Note the preserve of decimal places.

Default is six, the six extra does not display;
Nature does not convert into the buffer,

CodePudding user response:

reference QZJHJXJ reply: 3/f

this change, for reference:

 # include 
Int main () 
{
Int I; 
Char tmpbuffer [8] [20]. 
Double U13Coef [8]={0.000000428344451, 0.000041556454936, 0.001508777414466, 0.02414235618335, 
0.158289852824976, 1.54926741892562, 0.162671275351189, 0.55}; 
for (i=0; i<8; I++) 
{
Sprintf (tmpbuffer [I], "% 18.15 f," U13Coef [I]); 
Printf (" % s \ n ", tmpbuffer [I]); 
} 

return 0; 
} 


//0.000000428344451 
//0.000041556454936 
//0.001508777414466 
//0.024142356183350 
//0.158289852824976 
//1.549267418925620 
//0.162671275351189 
//0.550000000000000 
//please press any key to continue...

Pay attention to the length of column, 18 + 15 & gt; 20, so the length of 20 is inappropriate,