Requirements: don't put the number of intermediate can be divided exactly by 5 or 7 (1) and n included) included in the total number,
Input, your program should read the lines from standard input, each line contains a positive integer,
Output: the input of each line, will be of Numbers from 1 to n, and output to standard output, ignore those Numbers can be divided exactly by 5, and 7, print out each result in the new row,

CodePudding user response:

Then your code?

CodePudding user response:

Write programs as required to

 
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* https://bbs.csdn.net/topics/395126735 
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/* * 
* @ file sum. CPP 
* @ brief, 
*/

#include  
using namespace std; 

#include  

Static int 
The sum (int last) 
{
Int total; 

Total=0; 
For (int number=1; Number & lt;=last; Number++) {
If (number % 5==0 | | number % 7==0) 
continue; 
Total +=number; 
} 
Return the total; 
} 

Int 
The main (void) 
{
The string line; 

While (getline (cin, line)) {
Cout & lt; } 

return 0; 
} 

CodePudding user response:

I hope it can help you: https://blog.csdn.net/it_xiangqiang/category_10581430.html
I hope it can help you: https://blog.csdn.net/it_xiangqiang/category_10768339.html