2.3 the topic how to do

CodePudding user response:

2. The first write formulas in math, then into the formula in the program

CodePudding user response:

2 formula is n * (n - 1)/2 write code type n, then the output out

3 3 * 5 * 7, a total of 105 kinds of circumstances, to do loop from 1 to 105, look is more than a few meet in addition to the three 2, divided by 5 more than 3, divided by 7 more than 2; Assume that this number is n
Subtract with 2395 and 2333, respectively, n, and see which one is 105 multiples, which one is it,
Meet, divided by the number of the condition of a few more than a few 105 x + n
Of course, you can directly in 2395 and 2333 directly to remove the remainder whether meet the condition

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Fun

reference 2 floor response:

2 formula is n * (n - 1)/2 write code type n, then the output out

3 3 * 5 * 7, a total of 105 kinds of circumstances, to do loop from 1 to 105, look is more than a few meet in addition to the three 2, divided by 5 more than 3, divided by 7 more than 2; Assume that this number is n
Subtract with 2395 and 2333, respectively, n, and see which one is 105 multiples, which one is it,
Meet, divided by the number of the condition of a few more than a few 105 x + n
Of course, you can directly in 2395 and 2333 directly to remove the remainder whether meet the conditions of

Thank you for your trouble can ask you a question

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Are math problems, and programming

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I hope it can help you: https://blog.csdn.net/it_xiangqiang/category_10581430.html
I hope it can help you: https://blog.csdn.net/it_xiangqiang/category_10768339.html