Something wrong with the OJ2910 extract Numbers (ah)-CodePudding

#include
#include
Int main ()
{
Char a, [109].
Int x [109];
Gets (a);
Int len=strlen (a);
Int I, t=0, j, k, y=0;
For (I=0; i {
If (a [I] & gt;=49 & amp; & A [I] <=57)
{
For (j=I; A [j] & gt;=48 & amp; & A [j] <=57; J++)
{
X=[t] a [j] - 48;
t++;
}
I=j;
If (y & gt; 0)
{
For (k=y + 1; K & lt; t; K++)
{
Printf (" % d ", x [k]);
Y=k;
}
}
Else if (y==0)
{
For (k=0; K & lt; t; K++)
{
Printf (" % d ", x [k]);
Y=k;
}
}
printf("\n");
}
Else if (a==[I] 48 & amp; & (a + 1] [I & gt; 57 | | a [I + 1] <48))
{
Printf (" % c \ n ", a [I]);
}
}
return 0;
}

CodePudding user response:

What's the problem?

CodePudding user response:

Directly on the VJ WA changed many times

CodePudding user response:

I think you can put the topic posted, the only answer who understand what do you want to do

CodePudding user response:

This code do not have what problem, you can run on VS, the result is right,,,

CodePudding user response:

 # include 
#include 

Int main () 
{
Char a, [109]. 
Int x [109]; 

Gets (a); 
Int len=strlen (a); 
Int I, t=0, j, k, y=0; 
For (I=0; i {
If (a [I] & gt;='1' & amp; & A [I] <='9') {
X=[t++] a [I] - '0'; 
continue; 
} 
Printf (" % c ", a [I]); 
/* 
If (a [I] & gt;=49 & amp; & A [I] <=57) 
{
For (j=I; A [j] & gt;=48 & amp; & A [j] <=57; J++) 
{
X=[t] a [j] - 48; 
t++; 
} 
//I=j;//here will change the outer loop 
If (y & gt; 0) 
{
For (k=y + 1; K & lt; t; K++) 
{
Printf (" % d ", x [k]); 
Y=k; 
} 
} 
Else if (y==0) 
{
For (k=0; K & lt; t; K++) 
{
Printf (" % d ", x [k]); 
Y=k; 
} 
} 
printf("\n"); 
} 
Else if (a==[I] 48 & amp; & (a + 1] [I & gt; 57 | | a [I + 1] <48)) 
{
Printf (" % c \ n ", a [I]); 
} 
*/
} 
Putchar (10); 
For (I=0; i Printf (" % d ", x [I]); 
Putchar (10); 

return 0; 
}

For your reference ~

Extract the number, don't consider too complicated,

CodePudding user response:

 # include 
#include 

Int main () 
{
Char a, [128]. 
Int x [128]; 
Int len. 
Int I, t=0; 

Gets (a); 
Len=strlen (a); 

For (I=0; i {
If (a [I] & gt;='0' & amp; & A [I] <='9') {
X=[t++] a [I] - '0'; 
continue; 
} 
Printf (" % c ", a [I]); 
} 
Putchar (10); 
For (I=0; i Printf (" % d ", x [I]); 
Putchar (10); 

return 0; 
}

After optimization, for your reference ~ 0 is also in the category of digital

CodePudding user response:

I hope it can help you: https://blog.csdn.net/it_xiangqiang/category_10581430.html
I hope it can help you: https://blog.csdn.net/it_xiangqiang/category_10768339.html