C how escape character recognition-CodePudding

Input string, calculate the escape character/n,/a/b/t the number of such as 12 d/nb#, enter # or to stop printing, o great god answer

CodePudding user response:

It is not by the number of statistics/?

CodePudding user response:

reference 1st floor wowpH response:

that is not the number of statistics/?

But statistics letters

CodePudding user response:

refer to the original poster weixin_45846821 response:

input string, calculate the escape character/n/a,/b/t the number of such as 12 d/nb#, enter # or to stop printing, o great god answer

There is/, that how to identify?

CodePudding user response:

What don't understand,,,, how to identify one more to go,

CodePudding user response:

 
/* - 
* Copyright (C), 1999-2019, mymtom. 
* _ 
* ____ _ _ ____ _ | | _ _____ _____ 
* | \ | | | | (_ _) _ \ | \ 
* | | | | | _ | | | | | | | | | _ | | | | | 
* | _ | _ _ - | | \ | _ | _ _ - | | \ () ___/| _ | _ | _ | 
* (____/
* 
* vi: set ts=4 sw=4: 
*/

/* * 
C 
 * @ file LetterCount.* @ brief, 
*/

#include  

Static int 
Unescape (int ch) {
Int ret=0; 
If (' a '==ch) 
Ret='\ a'; 
Else if (' b '==ch) 
Ret='\ b; 
Else if (==ch 'f') 
Ret='\ f; 
Else if (==ch 'n') 
Ret='\ n'; 
Else if (==ch 'r') 
Ret='\ r; 
Else if (' t '==ch) 
Ret='\ t'; 
Else if (==ch 'v') 
Ret='\ n'; 
Return ret. 
} 

The static char * 
The escape (int ch, char * buf) {
Int ret=0; 
If (\ 'a'==ch) 
Ret='a'; 
Else if (==ch \ b) 
Ret='b'; 
Else if (==ch \ f) 
Ret='f'; 
Else if (=='\ n' ch) 
Ret='n'. 
Else if (==ch \ r) 
Ret='r'. 
Else if (' \ t '==ch) 
Ret='t'. 
Else if (==ch \ v) 
Ret='v'; 

If (0==ret) {
Buf [0]=ch; 
Buf [1]=0; 
} else {
Buf [0]='\ \'; 
Buf [1]=ret; 
Buf [2]=0; 
} 

Return buf. 
} 

Int 
The main (int arg c, char * argv []) 
{
int i; 
Int ch; 
Char buf [3]. 
Int count [256]={0}; 

While (EOF!=(ch=fgetc (stdin))) {
If (' # '==ch) 
break; 
If (' \ \ '==ch) {
Ch=fgetc (stdin); 
If (' # '==ch) 
break; 
Ch=unescape (ch); 
} 
The count [ch] + +; 
} 

For (I=0; I & lt; 256; I++) {
If (count [I] & gt; 0 {
Printf (" % s: 2.2%4 d \ n ", the escape (I, buf), the count [I]); 
} 
} 

return 0; 
}

CodePudding user response:

I hope it can help you: https://blog.csdn.net/it_xiangqiang/category_10581430.html
I hope it can help you: https://blog.csdn.net/it_xiangqiang/category_10768339.html