ID TYPE ORDER_INDEX CITY_ID
-----------------------------------
1 CAT 1 1
2 DOG 2 1
3 CAT 4 2
4 DOG 5 2
5 BEE 9 1
For each city I need to swap the order_index
of cat
and dog
.
So city with ID 1 should have cat=2 and dog=1, city with ID 2 would have cat=5 and dog=4.
How can this be done with pure SQL?
CodePudding user response:
Use an update:
UPDATE yourTable t1
SET ORDER_INDEX = (SELECT t2.ORDER_INDEX FROM yourTable t2
WHERE t2.CITY_ID = t1.CITY_ID AND
t2.TYPE IN ('CAT', 'DOG') AND
t2.TYPE <> T1.TYPE)
WHERE TYPE IN ('CAT', 'DOG');
The above update logic assumes that you wish to do the ORDER_INDEX
swap between dog/cat pair records having the same CITY_ID
.
CodePudding user response:
Well, if you don't care about ID
, then there's a simple option which does what you wanted:
Before:
SQL> select * from test order by id;
ID TYP ORDER_INDEX CITY_ID
---------- --- ----------- ----------
1 CAT 1 1
2 DOG 2 1
3 CAT 4 2
4 DOG 5 2
5 BEE 9 1
Update:
SQL> update test set
2 type = decode(type, 'DOG', 'CAT', 'DOG')
3 where type in ('CAT', 'DOG');
4 rows updated.
After; requirement was
city with ID 1 should have cat=2 and dog=1, city with ID 2 would have cat=5 and dog=4.
SQL> select * from test order by id;
ID TYP ORDER_INDEX CITY_ID
---------- --- ----------- ----------
1 DOG 1 1 --> city with ID = 1 has DOG = 1 ...
2 CAT 2 1 --> ... and CAT = 2
3 DOG 4 2 --> city with ID = 2 has DOG = 4 ...
4 CAT 5 2 --> ... and CAT = 5
5 BEE 9 1
SQL>