How to click a span Accordion with selenium python-CodePudding

I have been trying to use selenium python to click the Element1 or Element2 button in enter image description here

with this code :

element3=driver.find_elements_by_id("span.jump_1").click

element3=driver.find_element_by_css_selector("#jump_1 > button").click

I have tried several selectors, xpath..nothing seems working for me.

CodePudding user response：

There are 4 ways to click in Selenium.

I will use this xpath

//h3[@id='Element_1']

Code trial 1 :

time.sleep(5)
driver.find_element_by_xpath("//h3[@id='Element_1']").click()

Code trial 2 :

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//h3[@id='Element_1']"))).click()

Code trial 3 :

time.sleep(5)
button = driver.find_element_by_xpath("//h3[@id='Element_1']")
driver.execute_script("arguments[0].click();", button)

Code trial 4 :

time.sleep(5)
button = driver.find_element_by_xpath("//h3[@id='Element_1']")
ActionChains(driver).move_to_element(button).click().perform()

Imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains

Also if the id is unique, I would advise you to use id instead of xpath.

Also, I do not see Element 2 in HTML that you've shared.