I have a data set that contains the url to web pages. I have something like this :

• https://abc.eu/login or https://abc.eu/ or https://abc.eu/ar35gjdb4

I am trying to replace all the urls by what's after the last "/" so I'm simply using

df["url"].str.split("/").str[-1]

But I'd like for the urls that have a long string composed of both letters and numbers (like the third link) to be replaced by "valid" and those that have nothing at the end after the last "/" to be replaced by "home_page", how do I achieve that?

I'd like to have something like this:

• login
• home_page
• valid

CodePudding user response：

You can parse url with this. Then you can replace.

CodePudding user response：

Please find the code to achieve the above requirement:

urls = ["https://abc.eu/login", "https://abc.eu/", "https://abc.eu/ar35gjdb4"]

for url in urls:
    s = url.rsplit('/', 1)
    if s[1] == 'login':
        print(os.path.join(s[0], 'login'))
    elif s[1] == '': 
        print(os.path.join(s[0], 'home_page'))
    elif re.match('^[a-zA-Z0-9_] $', s[1]):
        print(os.path.join(s[0], 'valid'))