I need to formulate an iteration sequence that follows the output pattern below:

However my attempts insofar are yielding an output that returns back to iteration, rather than returning to a logical sequencing:

for i in range(10):
    if i==7:
        i=i-1
    print(i)

0
1
2
3
4
5
6
6
8
9

I feel as though I am overlooking something incredibly simple, or something that is an obvious syntactical error?!

CodePudding user response：

This is simpler

for i in range(9):
    if i==7:
        temp=i-1
        print(temp)
    print(i)

Your code is is causing you to over write your i value.

CodePudding user response：

Maybe you could try something like this:

def print_with_condition(limit, condition):
    for i in range(limit):
        if condition(i):
            print(i)
        print(i)


print_with_condition(9, lambda x: x == 6)

The above code would produce this result:

EDIT 1

If you want a simpler approach:

for i in range(10):
    if i != 9:
        if i == 6:
            print(i)
        print(i)

CodePudding user response：

The last number is not taken into account. You need to write for i in range(9)

CodePudding user response：

In your for loop , when i=7 we temporarily make i=6 and print it. But the for loop had run till the i=7 state , hence for the next iteration 'i' will be 8 due to for loop behavior, which explains your output. You can achieve your desired output , by printing i-1 for every iteration from when i=7.

Code:

for i in range(10):
    if i>=7:
        print(i-1)
    else:
        print(i)

Output:

CodePudding user response：

Just few lines of change in your code (added print inside if block) gives the desired results:

for i in range(9):
    if (i == 7):
       print (i-1)
    print (i)

OR if you still want to iterate until range(10), this is the code:

for i in range(10):
    if (i >= 7):
        print (i-1)
    else:
        print (i)

Output: