Python check if listelement is in value but return the listelement it found instead of true-CodePudding

mylist = ['dog','cat','bird']

var = "*ç%&dog*ç%"

a = any(mylist for mylist in var)
print(a)

This returns true, but i wan't it to return "dog" as a string. How can i do that?

CodePudding user response：

any() returns True if at least one of the elements in your list is True.

In your case, you better use list comprehension with condition:

a  = [x for x in mylist if x in var]
print(a)

Or you can use filter:

a = list(filter(lambda x: x in var, mylist))
print(a)

CodePudding user response：

Consider using a function to handle checking the word contained in the string, and return that word back if it exists.

def fn(word, var):
    if word in var:
        return word
    else:
        return None


for element in mylist:
    print(fn(element, var))