I want my code to return error if one of the parameter is negative How do that.

const sumAll = function(num1,num2) {
    let newArr = [num1,num2];
    let sortedArr = newArr.sort(function(a,b) {
        return a - b;
    })
    let lastArr = []
    for (let i = sortedArr[0]; i <= sortedArr[1];   i ) {
        lastArr.push(i)
    }
    let reducedArr = lastArr.reduce(function(previousValue,currentValue) {
        return previousValue   currentValue;
    })
    return reducedArr;
};

console.log(sumAll(1,-4));

CodePudding user response：

Try something like this

const sumAll = function(num1,num2) {
    if (num1 < 0 || num2 < 0) {
        throw "Num1 and num2 must not be negative"
    }
    let newArr = [num1,num2];
    let sortedArr = newArr.sort(function(a,b) {
        return a - b;
    })
    let lastArr = []
    for (let i = sortedArr[0]; i <= sortedArr[1];   i ) {
        lastArr.push(i)
    }
    let reducedArr = lastArr.reduce(function(previousValue,currentValue) {
        return previousValue   currentValue;
    })
    return reducedArr;
};

console.log(sumAll(1,-4));

If you want to return an error message instead of throwing an error, replace the word throw with the word return on line 3.

CodePudding user response：

If question is related to negative parameter check, I think you can use Math.sign() function for checking negativity/positivity of values.

Math.sign(-4) returns -1

Math.sign(4) returns 1

In if case it will be represents true/false

const sumAll = function(num1,num2) {
  if (Math.sign(num1) || Math.sign(num2)) {
    return "Parameters must be positive integer."
  }

  let newArr = [num1,num2];
  let sortedArr = newArr.sort(function(a,b) {
    return a - b;
  });

  let lastArr = [];

  for (let i = sortedArr[0]; i <= sortedArr[1];   i ) {
    lastArr.push(i);
  }

  let reducedArr = lastArr.reduce(function(previousValue,currentValue) {
    return previousValue   currentValue;
  });

  return reducedArr;
 };
    
console.log(sumAll(1,-4));