Defines an int type variable k, and assign a value of 97, when used alone % c format output (printf (" % k=c \ n ", k);) Display properly for a, but the k and several other variables with a printf output, the result is changed, can't really understand why

 
#include  

Int main () 
{
Float the I, j; 
Int k; 
Char m; 

I=1.0/3.0; 
J=0.33333333; 
K=97; 
M=111; 
Printf (" I=% f \ n ", I); 
Printf (" j=% d \ n ", j); 
Printf (" % k=c \ n ", k); 
Printf (" m=c \ % n, m); 
Printf (" I=% f j k==% d % % c m=c \ n ", I, j, k, m); 

return 0; 
} 

After the operation is such, to solve!

CodePudding user response:

I think this is a float with you j, but use % d to print on,
Print parameter is a variable, function internally by printing format to find parameters, separate print print (" % d \ n, j); When only one parameter j, even if the type does not match, also does not affect the parameters of the search (only the length of the intercept parameter different); And together to print, print search parameters, because of the type of % d and j, in the right length, interception parameters affect the next parameter search,
For example, j memory information of 01010111
According to the interception of 0101
% dLeft behind 0111
Continue to capture % c k parameter, directly will take the remaining 0111, so k is wrong
Continue to take % c m parameters, truly achieved k information, so m print out the information for a k

CodePudding user response:

Data type problems
Printf (" I=% f \ n ", I);
Printf (" j=% d \ n ", (int), j);
Printf (" % k=c \ n ", k) (char);
Printf (" m=c \ % n, m);
Printf (" I=% f j k==% d % % c m=c \ n ", I, j (int), k (char), m);

CodePudding user response:

reference 1st floor qybao response:

I think this is a float with you j, but use % d to print on,
Print parameter is a variable, function internally by printing format to find parameters, separate print print (" % d \ n, j); When only one parameter j, even if the type does not match, also does not affect the parameters of the search (only the length of the intercept parameter different); And together to print, print search parameters, because of the type of % d and j, in the right length, interception parameters affect the next parameter search,
For example, j memory information of 01010111
According to the interception of 0101
% dLeft behind 0111
Continue to capture % c k parameter, directly will take the remaining 0111, so k is wrong
Continue to take % c m parameters, truly achieved k information, so m print out the information for a k

Thank you answer
The original printf is not so simple

CodePudding user response:

reference 1st floor qybao response:

I think this is a float with you j, but use % d to print on,
Print parameter is a variable, function internally by printing format to find parameters, separate print print (" % d \ n, j); When only one parameter j, even if the type does not match, also does not affect the parameters of the search (only the length of the intercept parameter different); And together to print, print search parameters, because of the type of % d and j, in the right length, interception parameters affect the next parameter search,
For example, j memory information of 01010111
According to the interception of 0101
% dLeft behind 0111
Continue to capture % c k parameter, directly will take the remaining 0111, so k is wrong
Continue to take % c m parameters, truly achieved k information, so m print out the information for a k

Again for the great god, or on the cases, delete the last line of the printf, direct assignment and m=0, the output is m=a is how to return a responsibility? Assignment 1, 2, 3 and so on can and ASCII table, it happened that 0 wrong