I want to show n and the number of factors (excluding 1 and itself) of n. like this example

n factor
1   0
2   0
3   0
4   1
5   0
6   2
7   0
8   2
9   1
10  2

So I wrote the code like this my code

n = int(input('Enter the number: '))

factor = 0

for a in range(1, n 1):

    if n % a == 0:
        factor  = 1
    fctr = factor - 2
        
    print("%d" '\t' "]" %(a, fctr))

I don't know why it doesn't work. I've been thinking about it for two days, but I still don't get it why it's not working. Did I write "for" incorrectly?

CodePudding user response：

If you want number of factors for all the numbers from 1 to n you should write two for loops (nested one). One for iterating through numbers from 1 to n and the other for finding numbers of factors for ath number.

So this solves the problem -

n = int(input('Enter the number: '))

for a in range(1, n 1):
    factor = 0

    for b in range(2, a):

        if a % b == 0:
            factor  = 1
        
    print("%d" '\t' "]" %(a, factor))

CodePudding user response：

You're doing

    fctr = factor - 2

for every iteration of the loop

    for a in range(1, n 1):

That would probably give you a negative value in the very beginning. Since you know you just don't want to count 1 and n why not run the loop as:

    for a in range(2, n):

Based off of your example, are you trying to print the number of factors of each number from 1 to n? Because that would require another outer for loop. Right now you're only printing the number of factors of n (seen so far at every point of the loop).