Im trying to figure out how this validate phone number to my android works.
I have add the code and whant to validate 46123456789 but the last number (9) doesent add to the phone number.
This i use:
/**
* @param phone
* @return The number which satisfies the above criteria, is a valid mobile Number.
* The first digit should contain number between 0 to 9.
* The rest 9 digit can contain any number between 0 to 9.
* The mobile number can have 11 digits also by including 0 at the starting.
* The mobile number can be of 12 digits also by including 46 at the starting
*/
public static boolean isValidPhoneNumber(String phone) {
phone = trimPhoneNumber(phone);
// The given argument to compile() method
// is regular expression. With the help of
// regular expression we can validate mobile
// number.
// 1) Begins with 0 or 46
// 2) Then contains 6 or 7 or 8 or 9.
// 3) Then contains 9 digits
Pattern p = Pattern.compile("(0/46)?[0-9][0-10]{9}");
// Pattern class contains matcher() method
// to find matching between given number
// and regular expression
Matcher m = p.matcher(phone);
return (m.find() && m.group().equals(phone));
}
public static String trimPhoneNumber(String phone) {
if (TextUtils.isEmpty(phone)) {
return phone;
} else {
try {
phone = phone.replace(" 46", "");
phone = phone.replaceAll("[^0-9]", "");//replace all except 0-9
return phone;
} catch (Exception e) {
e.printStackTrace();
return phone;
}
}
}
Am i missing something
CodePudding user response:
Use this pattern:
^\s*(?:(?:\ ?46)|0)(?:\d){9,10}\s*$
^
at start and $
at end ensure pattern matches the whole input
\s*
trim any space or tab
\d
capture any digit
(?:\d){9,10}
means the pattern (?:\d)
should be repeated 9 to 10 times.
``
Pattern start with ( 46
or 46
) or 0
follow by 9 or 10 digit.
If it could contain -
or space between numbers, use this:
^\s*(?:(?:\ ?46)|0)(?:[- ]*\d){9,10}\s*$
You could test regex here