How to generate random number into an empty list multiple time-CodePudding

Lets say I want to find all the numbers a fair die can roll sample_size of times.

I first create a empty list

die_list= []
def die_number(sample_size)：
    for i in range(sample_size) #i want to iterate what ever the sample_size is
    die_list.append(random.randint(0,7))

is this thought process correct?

CodePudding user response：

Based on the sample code provided,you can try this out using list comprehension

import random

def die_number(sample_size):
  return [random.randint(0, 100) for x in range(sample_size)]

die_number(5)

[29, 0, 2, 100, 51]

CodePudding user response：

The thought process is basically correct, and your code can be made to work once the syntax and indentation errors are ironed out:

import random

die_list= []

def die_number(sample_size):
    for i in range(sample_size):  # I want to iterate whatever the sample_size is
        die_list.append(random.randint(1,6))

die_number(10)
print(die_list)

However, the code still feels a little weird. That's because it is more idiomatic (“pythonic”) to have the die_number function create the list, populate it and ultimately return it to the caller. Like this:

import random

def die_number(sample_size):
    die_list = []
    for i in range(sample_size):  # I want to iterate whatever the sample_size is
        die_list.append(random.randint(1,6))
    return die_list

dies = die_number(10)
print(dies)