Knockout js foreach binding alphabetically-CodePudding

I'm totally new in knockout.

Good you help me to understand how I need to change this code:

<ol class="items" data-bind="foreach: getDisplayedItems()">
    <li class="item">
        <a class="simple" data-bind="html: label, attr: {href:url}, visible: count >= 1, css: { active: is_selected }"></a>
        <span class="count" data-bind="text: count"></span>
    </li>
</ol>

to make it in alphabetically order?

Thanks for any tips Regards

CodePudding user response：

You could sort them in-place:

<ol class="items" data-bind="foreach: getDisplayedItems().sort((a, b) => ko.unwrap(a.label) < ko.unwrap(b.label) ? -1 : 1)">
    <li class="item">
        <a class="simple" data-bind="html: label, attr: {href:url}, visible: count >= 1, css: { active: is_selected }"></a>
        <span class="count" data-bind="text: count"></span>
    </li>
</ol>

but I think that's ugly, and it's not re-usable. It's better to make a new observable array that contains the items in the right order:

function App {
    // the observable you already have
    this.getDisplayedItems = ko.observableArray([...]);

    // a computed observable based on that
    this.getDisplayedItemsAlphabetical = ko.pureComputed(() => {
        var itemsCopy = [...this.getDisplayedItems()];
        return itemsCopy.sort((a, b) => ko.unwrap(a.label) < ko.unwrap(b.label) ? -1 : 1);
    });
}

and

<ol class="items" data-bind="foreach: getDisplayedItemsAlphabetical">