I have List of products with product name and date. I want to sort that list of items based on date and time. This is the list of items that i want to sort,
List items = [
{
"productName":"Icecream",
"date":"2019-10-17 10:06:12.278"
},
{
"productName":"Juice",
"date":"2021-09-20 19:08:16.274"
},
{
"productName":"Rice",
"date":"2020-05-13 08:02:16.177"
},
{
"productName":"Cheese",
"date":"2021-10-23 20:02:16.254"
},
{
"productName":"Sugar",
"date":"2019-11-22 00:00:00.000"
},
];
This is the Expected Output what i want,
List sortedList = [
{
"productName":"Icecream",
"date":"2019-10-17 10:06:12.278"
},
{
"productName":"Sugar",
"date":"2019-11-22 00:00:00.000"
},
{
"productName":"Rice",
"date":"2020-05-13 08:02:16.177"
},
{
"productName":"Juice",
"date":"2021-09-20 19:08:16.274"
},
{
"productName":"Cheese",
"date":"2021-10-23 20:02:16.254"
},
];
CodePudding user response:
This is a simple code using the build-in function .compareTo
that can help you out:
void main() async {
List items = [
{"productName": "Icecream", "date": "2019-10-17 10:06:12.278"},
{"productName": "Juice", "date": "2021-09-20 19:08:16.274"},
{"productName": "Rice", "date": "2020-05-13 08:02:16.177"},
{"productName": "Cheese", "date": "2021-10-23 20:02:16.254"},
{"productName": "Sugar", "date": "2019-11-22 00:00:00.000"},
];
// You can change the position of `a` and `b` to get a reversed result
// as well
items.sort((a, b) => a['date'].compareTo(b['date']));
print(items);
}
CodePudding user response:
you can use compareTo
method in list to compare results based on these results you can sort list using .sort
method on list