Example here:
gitrepo=$(jq -r '.gitrepo' 0.json)
releasetag=$(curl --silent ""https://api.github.com/repos/\"$gitrepo\""/releases/latest" | grep '"tag_name":' | sed -E 's/.*"([^"] )".*/\1/')
echo "$releasetag"
Used \"
to escape characters.
0.json:
{
"type": "github-releases",
"gitrepo": "ipfs/go-ipfs"
}
How to put $gitrepo to work inside $releasetag? Thanks in advance!
CodePudding user response:
Bash variables expand inside quoted "
strings.
gitrepo="$(jq -r '.gitrepo' 0.json)"
releasetag="$(
curl --silent "https://api.github.com/repos/$gitrepo/releases/latest" \
| grep '"tag_name":' | sed -E 's/.*"([^"] )".*/\1/'
)"
echo "$releasetag"
Btw, as you are using jq
to extract .gitrepo
from 0.json
, you could also use it in the exact same way to extract .tag_name
from curl
's output (instead of using grep
and sed
) like so:
gitrepo="$(jq -r '.gitrepo' 0.json)"
releasetag="$(
curl --silent "https://api.github.com/repos/$gitrepo/releases/latest" \
| jq -r '.tag_name'
)"
echo "$releasetag"
And to simplify it even further (depending on your use case), just write:
curl --silent "https://api.github.com/repos/$(jq -r '.gitrepo' 0.json)/releases/latest" \
| jq -r '.tag_name'