Python - displaying conic sequence with only 4 digit sequencing-CodePudding

I am writing a program to determine the conic sequence of a user's inputted data set, for example - [0000,1,2222,9999],

I was struggling with sequencing the conic sequence using only a 4 digit classification, instead of the typical 8/16 binary approaches.

I have tried this:

for t in permutations(numbers, 4):
print(''.join(t))

But it does not assign a unique value to the inputted data, and instead overrides previous ones.

How can I go about doing this?

CodePudding user response：

Since your list only contains the numbers 0 through 9 and you're looping over that list, printing the content as you go, it will only print 0 through 9.

Since all possible combinations (or rather permutations, because that's what you're asking about) of the normal decimal digits are just the numbers 0 through 9999, you could do this instead:

for i in range(10000):
    print(i)

See https://docs.python.org/3/library/functions.html#func-range for more on range().

But that doesn't print numbers like '0' as '0000'. To do that (in Python 3, which is probably what you should be using):

for i in range(10000):
    print(f"{i:04d}")

See https://docs.python.org/3/reference/lexical_analysis.html#f-strings for more on f-strings.

Of course, if you need permutations of something other than digits, you can't use this method. You'd do something like this instead:

from itertools import permutations

xs = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']

for t in permutations(xs, 4):
    print(''.join(t))

See https://docs.python.org/3/library/itertools.html#itertools.permutations for more on permutations() and the difference with combinations().

CodePudding user response：

You can also do something like this, if you want to change some information by the future :

import math

NUMBERS = [0,1,2,3,4,5,6,7,8,9]
DIGITS = 4
MAX_ITERS = int(math.pow(len(NUMBERS), DIGITS))

for i in range(MAX_ITERS):
    print(f"{i:04d}")