Help: Java programming: using the recursive function call, will enter the ten characters, printed in-CodePudding

As title, thanks for your bosses ~ ~
I haven't learn recursion is what,,, ah it,,,,

CodePudding user response:

Recursion is call themselves, in the method with judgment decision is to continue to call themselves, or the end of the call,

CodePudding user response:

reference 1st floor aw277866304 response:

is recursive call themselves, in the way with judgment decision is to continue to call themselves, or the end of the call,

Ah yes, I go to Chou Chou

CodePudding user response:

 static Scanner input=new Scanner (System. In); 
Public static void test1 () {
System. The out. Println (" please enter the characters no end "); 
Xx=input String. The next (); 
If (" no ". The equals (xx)) 
return ; 
test1(); 
System. The out. Print (xx + "\ t"); 
Second}

 public static void test2 (String [] arr, int index) {
If (arr. Length==index) return; 
Test2 (arr, index + 1); 
[index] System. Out. Println (arr); 
}

CodePudding user response:

 package test. Gt80; 

Public class Test98 {

Public static void main (String [] args) throws the Exception {
String STR="12345"; 
Test (STR, STR. Length ()); 
} 

Public static void test (String STR, int length) {
If (length==0) 
return; 
System. The out. Print (STR. CharAt (length - 1)); 
The test (STR, length - 1); 
} 
}

CodePudding user response:

 public class Test2 {

Public static void main (String [] args) {

String param="people is my country in the"; 

System. The out. Println (doEvert (param)); 

} 

Public static String doEvert (String param) {
If (StringUtils. IsEmpty (param. The trim ())) {
Return param. 
} 
If (param length ()==1) {
Return param. 
} 
Return param. Substring (param length () - 1) + doEvert (param. Substring (0, param. Length () - 1)); 
} 
}