I'm opening a csv file in Excel with an Access macro. I'm doing this to get the file name and then use the TransferText function to import the file into an Access table.
I would like to specify a default path to eliminate some of the navigation for the end user. I've tried ChDrive and ChDir but The GetOpenFileName still takes me to a personal drive on the network.
Below is the code I'm using. Any suggestions or advice would be greatly appreciated/ Thanks in advance.....
Set ExcelApp = CreateObject("Excel.Application")
ExcelApp.Visible = True
ChDrive "V:"
ChDir "V:\Accounting\Projects\In Work\Project Database\"
RawData = ""
RawData = ExcelApp.Application.GetOpenFilename
Set ExcelApp = Nothing
DoCmd.TransferText acImportDelim, , "tbl_Stage", RawData, True
CodePudding user response:
You need to change the drive and folder of the Excel object. At the moment, you're changing the drive and folder of the Access object.
Excelapp.DefaultFilePath = "V:\Accounting\Projects\In Work\Project Database\"
Unless you are using a very old version of Excel, you can use the FileDialog object for more control:
Set FD = Excelapp.FileDialog(msoFileDialogFilePicker)
With FD
.InitialFileName = ActiveDocument.Path
.Show
End With
exFile = FD.SelectedItems(1)