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The problem of encryption

Time:09-21

Excuse me, ladies and gentlemen:
After 0000001 encryption is LACMHAA
After 0000002 encryption is LACMHAB
After 0000003 encryption is LACMHA7
After 0000004 encryption is LACMHAH
After 0004851 encryption is WPK9BQE
After 90420137 encryption is 8 atph579
After 000999 encryption is XYCTHVM
After 90420121 encryption is 8 atph5bq

What's this algorithm, how to decrypt?

CodePudding user response:

The encryption, is generally difficult to break, to master, ha ha

CodePudding user response:

Don't know oh, encryption cipher, the onlookers,,,,

CodePudding user response:

Encryption methods can have ten million kinds of...
Only people who happen to you using this method can give an answer immediately,

CodePudding user response:

Hen:

CodePudding user response:

Decryption is too difficult, the general condition is a solution, only by a few lines of code, is unable to decrypt,

CodePudding user response:

Ok see, from the perspective of the analysis of rough, perhaps encryption method is simple, but to completely break may still need to spend some time:
Tip: look from the last character, the first five lines, the original text in 1-4, a regular cipher (about 4 modulus)
Cipher plaintext
A 1
2 B
3 C
4 D
E 1
F 2
3 G
.
Q 1
R 2
In addition, 90 8 A, seems to be 80 + 10 (A)
But to crack need to spend time with yourself slowly whole, get some more samples,
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