How do you delete all hidden and non-hidden files except one in bash?-CodePudding

I have a question. How do you delete all hidden and non-hidden files except one in bash? BEcause I am creating a repository, and just now creating a update script.

CodePudding user response：

I would use the extended globbing and dot-globbing features of bash:

shopt -s dotglob extglob
cd /path/to/clean && rm !(file-name-to-keep)

CodePudding user response：

This will delete everything in the current directory that you have permission to remove, recursively, preserving the file named by -path, and its parent path.

# remove all files bar one
find . -mindepth 1 -not -type d -not -path ./file/to/keep -exec rm -rf {}  

# then remove all empty directories
find . -mindepth 1 -type d -exec rmdir -p {}   2>/dev/null

rmdir will get fed a lot of directories its already removed (causing error messages). rmdir -p is POSIX. This would not work without -p.

You can keep more files with additional -path arguments, and/or glob patterns. The paths must match the starting point, ie. ./.

CodePudding user response：

This would delete all files (not directories) in the current directory apart from "file-x":

rm `find . -maxdepth 1 -type f | grep -v "^\./file-x\$"`

The find creates a list of all files (including hidden ones). The "grep -v" removes the line "./file-x" from that list.