I need to find the last finish task using sql in each group. I have two conditions. construction_type = 0
and construction_type in (1, 2)
. For construction_type = 0
. Only completed task will be fetch. But for construction_type in (1, 2)
. Completed and not completed task can be fetch. I made the query but the problem is if tasks are finish and some new task enter which is not completed then this non completed task is coming at top. I tried different order by but somehow unable to get the last completed task at top in case of
construction_type in (1, 2)
. For construction_type = 0
there is no problem because only the completed tasks will be fetch.
I am ordering by on task_last_modified_date. If some new task will enter then it has highest task_last_modified_date. That's why my uncompleted task is coming on top. It should be something like latest task_last_modified_date with completed task
. But I am not sure how do I do it.
Here is the sample data
CREATE TABLE project_complete_data (CONSTRUCTION_TYPE, PROJECT_ID, PROJ_COMPANY_NAME, CUSTOM_LOT_NO, LOT_STATUS, SCHEDULE_TASK_ID, TASK_NAME, TASK_STATUS, TASK_ACTUAL_END_DATE, TASK_FINISH_DATE, TASK_FINISHED, TASK_LAST_MODIFIED_DATE, PO_TOTAL_AMOUNT, PO_STATUS, PO_TYPE) AS
SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961162, 'electrical rough', 101, DATE '2021-12-13', DATE '2021-11-19', 0, TO_DATE('2021-11-16 14:44:04', 'YYYY-MM-DD hh24:mi:ss'), 49.7, 100, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961161, 'plumbing rough', 101, DATE '2021-12-06', DATE '2021-11-12', 1, TO_DATE('2021-11-15 15:22:13', 'YYYY-MM-DD hh24:mi:ss'), 0.3, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961159, 'roof framing', 101, DATE '2021-11-29', DATE '2021-11-15', 1, TO_DATE('2021-11-15 13:04:37', 'YYYY-MM-DD hh24:mi:ss'), 10, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961158, 'second floor framing', 101, DATE '2021-11-15', DATE '2021-11-09', 1, TO_DATE('2021-11-09 15:22:42', 'YYYY-MM-DD hh24:mi:ss'), 50, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961157, 'first floor framing', 101, DATE '2021-11-08', DATE '2021-11-09', 1, TO_DATE('2021-11-09 14:44:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '0000000077', 102, 10961157, 'first floor framing', 101, DATE '2021-11-08', DATE '2021-11-09', 1, TO_DATE('2021-11-09 14:44:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '01a', 103, 10134563, 'Rough-In Plumbing', 101, DATE '2009-12-17', DATE '2014-09-01', 1, NULL, 0, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '02', 103, 2213016, 'Update Lender Info in BT - Sales Rep', 101, DATE '2005-06-28', DATE '2005-10-11', 1, NULL, 0, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '020', 103, 10955239, 'TK task', 101, DATE '2018-11-07', DATE '2019-06-21', 1, TO_DATE('2019-06-21 18:12:21', 'YYYY-MM-DD hh24:mi:ss'), 0, 100, 101 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', '020', 103, 10955239, 'TK task', 101, DATE '2018-11-07', DATE '2019-06-21', 1, TO_DATE('2019-06-21 18:12:21', 'YYYY-MM-DD hh24:mi:ss'), 33, 100, 100 FROM DUAL
UNION ALL SELECT 1, 511, 'Amber Hills Inc.', 'testpa01', 102, 10959716, 'HVAC rough', 101, DATE '2021-09-17', DATE '2021-09-15', 0, TO_DATE('2021-11-02 12:28:57', 'YYYY-MM-DD hh24:mi:ss'), 0, 101, 100 FROM DUAL;
Here is the query
select
proj_company_name,
custom_lot_no,
task_name,
task_actual_end_date,
task_finish_date,
task_finished,
task_last_modified_date,
to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') AS TASK_LAST_MODIFIED_DATE_TIME,
ROW_NUMBER() OVER (PARTITION BY custom_lot_no ORDER BY to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') desc) AS LAST_TASK_FINISH_SEQ,
po_total_amount,
po_status,
CASE
WHEN po_status = 101 THEN po_total_amount
ELSE 0
END as POs_COMPLETED,
po_type,
CASE
WHEN po_type = 100 THEN po_total_amount
ELSE 0
END as "COMMITTED"
FROM project_complete_data
where project_id = 511
AND po_status in ('100', '101')
AND lot_status in ('102', '103')
And task_status = 101
AND (
(construction_type = 0 AND task_finished = 1 and (schedule_task_id is not null or schedule_task_id > 0))
OR (construction_type in ('1', '2') AND task_finished in ('1', '0'))
)
order by custom_lot_no, to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss') desc;
This query is giving the following result
As you can see the top record has highest last_modified_date_time and it is coming at last_task_finish_seq at 1. But this task is not completed becasue its task_finished is 0
. So the first record should be the second one becasue although it last_modified_date_time is less but it is completed. And it is completed in last because it has higher last_modified_date_time then other completed tasks.
How can I do it? Actually after getting each group record on top I will use some thing like
`select * from (above query) where LAST_TASK_FINISH_SEQ = 1;`
Because then I know that I have the last completed task at top of each group.
Thanks
CodePudding user response:
To get the most recently completed row (or the latest row, if no rows are completed and construction_type IN (1,2)
), you can use:
SELECT *
FROM (
SELECT *
FROM project_complete_data
WHERE project_id = 511
AND po_status IN (100, 101)
AND lot_status IN (102, 103)
AND task_status = 101
AND ( ( construction_type = 0
AND task_finished = 1
AND schedule_task_id IS NOT NULL)
OR construction_type IN (1, 2)
)
)
MATCH_RECOGNIZE (
PARTITION BY custom_lot_no
ORDER BY task_finished DESC, task_last_modified_date DESC
ALL ROWS PER MATCH
PATTERN ( ^ latest_finished_row )
DEFINE
latest_finished_row AS 1 = 1
)
If you want to order the rows without filtering:
select proj_company_name,
custom_lot_no,
task_name,
task_actual_end_date,
task_finish_date,
task_finished,
task_last_modified_date,
to_char(task_last_modified_date, 'YYYY-MM-DD hh24:mi:ss')
AS TASK_LAST_MODIFIED_DATE_TIME,
ROW_NUMBER() OVER (
PARTITION BY custom_lot_no
ORDER BY task_finished DESC, task_last_modified_date desc
) AS LAST_TASK_FINISH_SEQ,
po_total_amount,
po_status,
CASE
WHEN po_status = 101
THEN po_total_amount
ELSE 0
END as POs_COMPLETED,
po_type,
CASE
WHEN po_type = 100
THEN po_total_amount
ELSE 0
END as "COMMITTED"
FROM project_complete_data
where project_id = 511
AND po_status in (100, 101)
AND lot_status in (102, 103)
And task_status = 101
AND ( ( construction_type = 0
AND task_finished = 1
AND schedule_task_id is not null
)
OR ( construction_type in (1, 2)
AND task_finished in (1, 0)
)
)
order by custom_lot_no, task_last_modified_date desc;
db<>fiddle here