I am writing this program, in which we need to convert the input from the user from digits into words. I've written the whole program. The only error I am facing is that when I write e.g. 4200, the zeros aren't appearing. I am a beginner at C .

while (num > 0)
{
    rem = num % 10;
    sum = sum * 10   rem;
    num = num / 10;
}
num = sum;

while (num > 0)
{
    rem = num % 10;
    switch (rem)
    {
        case 1 :
            cout << "One " ;
            break;
        case 2:
            cout << "Two " ;
            break;
        case 3:
            cout << "Three " ;
            break;
        case 4:
            cout << "Four " ;
            break;
        case 5:
            cout << "Five " ;
            break;
        case 6:
            cout << "Six " ;
            break;
        case 7:
            cout << "Seven "  ;
            break;
        case 8:
            cout << "Eight "  ;
            break;
        case 9:
            cout << "Nine "  ;
            break;
        case 0:
            cout << "Zero "  ;
            break;

Please help me out. How can I print the zeros too?

CodePudding user response：

Your solution is not optimal. So, I have written a new solution.

Solution

int num;
cin >> num;
vector<string> v;

while (num > 0) {
    switch (num % 10) {
        case 1:
            v.push_back("One");
            break;
        case 2:
            v.push_back("Two");
            break;
        case 3:
            v.push_back("Three");
            break;
        case 4:
            v.push_back("Four");
            break;
        case 5:
            v.push_back("Five");
            break;
        case 6:
            v.push_back("Six");
            break;
        case 7:
            v.push_back("Seven");
            break;
        case 8:
            v.push_back("Eight");
            break;
        case 9:
            v.push_back("Nine");
            break;
        case 0:
            v.push_back("Zero");
            break;
    }
    num /= 10;
}
reverse(v.begin(), v.end());
for (auto a: v) cout << a << " ";

You also can use map instead of switch.
If you get any errors try to write #include <vector>.

Very simple solution

int num;
cin >> num;
string s;
while (num > 0) {
    switch (num % 10) {
        case 1:
            s = "One "   s;
            break;
        case 2:
            s = "Two "   s;
            break;
        case 3:
            s = "Three "   s;
            break;
        case 4:
            s = "Four "   s;
            break;
        case 5:
            s = "Five "   s;
            break;
        case 6:
            s = "Six "   s;
            break;
        case 7:
            s = "Seven "   s;
            break;
        case 8:
            s = "Eight "   s;
            break;
        case 9:
            s = "Nine "   s;
            break;
        case 0:
            s = "Zero "   s;
            break;
    }
    num /= 10;
}
cout << s;

CodePudding user response：

If your goal is simply to convert digits as-is into words, there is a much simpler approach:

string input;
cin >> input;

for (char ch : input)
{
    switch (ch)
    {
        case '1':
            cout << "One " ;
            break;
        case '2':
            cout << "Two " ;
            break;
        case '3':
            cout << "Three " ;
            break;
        case '4':
            cout << "Four " ;
            break;
        case '5':
            cout << "Five " ;
            break;
        case '6':
            cout << "Six " ;
            break;
        case '7':
            cout << "Seven "  ;
            break;
        case '8':
            cout << "Eight "  ;
            break;
        case '9':
            cout << "Nine "  ;
            break;
        case '0':
            cout << "Zero "  ;
            break;
    }
}