I'm using re.split() and trying to join the elements but it doesn't work. Why is it?-CodePudding

I have a problem and I can't find reason why. I want to divide the string into 3 parts, and the condition is "integer Letter *(optional)" it works well when the number is one digit, but it doesn't work when the number is two digits.

This is my code:

import re
dartResult = '10S*3T2D*'
dartresult = re.split('(\d)',dartResult)   
dartresult=[i for i in dartresult if i != ""]
score = []
for i in range(len(dartresult)):
    try:
        if int(dartresult[i]):
            score.append(["".join(dartresult[i:i 2])])
        elif int(dartresult[i]) and int(dartresult[i 1]):   #in case the number is two digits
            score.append(["".join(dartresult[i:i 3])])    
    except:
        pass
print(dartresult)
print(score)

and this is the result.

['1', '0', 'S*', '3', 'T', '2', 'D*']
[['10'], ['3T'], ['2D*']]

and it would be nice if you let me know if there's a better way to divide the strings according to the condition above.

CodePudding user response：

Why don't you simply define all the elements in your regex?

import re
dartResult = '10S*3T2D*'
out = re.findall(r'\d \w\*?', dartResult)

output:

>>> out
['10S*', '3T', '2D*']

regex:

\d      # one or more digits
\w      # one character (letters/digit/underscore), to restrict to letters use [a-zA-Z]
\*?     # optionally, one "*" character

CodePudding user response：

Put a immediately after your \d to capture any consecutive characters that are numerals.