I checked with debugging also it is going to statement =>if(sum==1) return true; but then also it is executing further statements.

static long solve(int l, int r){
    // Your code goes here
    long sum=0;
    boolean t=0;
    for (int i=l;i<=r;i  ) {
        t=beautiful(i);
        if (t==true) {
            sum=sum i;
        }
    }
    return sum;
}

static boolean beautiful(int num) {
    if (num<=0) return false;
    if (num==1) return true;
    int sum=0;
    while (num>0) {
        int rem=num%10;
        sum=sum rem*rem;
        num=num/10;
    }
    if (sum==1) {
        System.out.print("some");
        return true;
    }
    System.out.print("one");
    beautiful(sum);
    return false;
}

CodePudding user response：

After then you call beautiful method, it goes into it and gets the result and continues. So you can do this despite you call beautiful method and return false;

return beautiful(sum);