loop in bash does not perform integer comparison properly-CodePudding

I have below code

i=0
for s in / - \\ \| 
do 
  printf "\rWaiting for application start to finish $i $s"
  sleep 1
  ((i  ))
  if [[ $i -gt 30 ]]
  then 
    break 
  fi
done

The loop always ends after 3 iterations. Any reason as why?

CodePudding user response：

My mistake. The for loop which has three arguments is exiting instead of the if condition failing.

CodePudding user response：

This might be what you are looking for:

#!/bin/bash

a=('/' '-' '\' '|')
for ((i = 0; i < 30;   i)); do
    printf '\rWaiting for application start to finish %d %s' \
            "$i" "${a[i%4]}"
    sleep 1
done
echo