Consider the following command:
git clean -n -x -d
This produces output of the following form:
Would remove path/to/file/1
Would remove untracked/directory
I would like to run a different command X on these files, but the extra Would remove prefix is not useful.
I could run sed or cut to kill this prefix.
git clean -n -x -d | cut -c 14-
However, I'm curious about whether there's a lower level git plumbing command I can use the get the output I want without starting another process.
git ls-files --other seemed promising, but unfortunately, its output includes all the files, instead of just the directory containing all the files.
path/to/file/1
untracked/directory/file1
untracked/directory/file2
...
Is there a low-level git command to replicate the output of git clean above without the extra prefix, or is my cleanest option just to cut out the prefix?
CodePudding user response：
If you need to get near git's plumbing, you can list untracked files with:
git ls-files --others
Alternatively, you can stick with commonly known tools, i.e.
git status --short --ignored | grep '!!\|??'
Documentation: