If I want to list the files of a directory and save the results in a res.txt
I can run the command
ls -l > res.txt
Now I would like to do the same in a process spawned from the main process of Node.
I have tried naively this
spawn(
'ls',
['-l', '>', 'res.txt'],
);
but does not work. Is there any way to achieve what i want?
CodePudding user response:
After some more googling I found that the shell: true
option does the trick.
So, if I want a spawned process to run a command which streams its output to a file, I can use this approach
spawn(
'ls -l > res.txt',
[],
{shell: true}
);
CodePudding user response:
so from the node documentation, which can be found here:
https://nodejs.org/api/child_process.html#child_processspawncommand-args-options
const { spawn } = require('child_process');
const ls = spawn('ls', ['-lh', '/usr']);