using namespace std;
Int main ()
{
Int a [10], I;
Cout<& lt;" Plesae input 10 Numbers: "& lt;
cin> A, [I].
Int j, s;
for(i=0; i<9. Bubble sort i++)//process
for(j=0; j<9 - I; J++)
{
If (a [I] & gt; A [I + 1])
S=a [I];
A [I]=a, [I + 1].
A [I + 1]=s;
}
Cout<& lt;" The result is: "& lt;
{
Cout
{
If (a [I]!=a [] I - 1)//repeat the number of output
Cout<& lt;" "& lt;
Goto o;//program skip to end
}
The else
{
Coutfor(i=2; i<10; I++)
{
If (a [I]!=] [I - 1 a)
Cout<& lt;" "& lt;
}
O: cout
return 0;
}
This code is bubble sort, repeated output data of several output only once, consult everybody, thank you!
CodePudding user response:
You are two Numbers equal time should use the==, rather than=CodePudding user response:
for(i=0; i<9. Bubble sort i++)//processfor(j=0; j<9 - I; J++)
To explain in detail what is the meaning of this thank you
CodePudding user response:
Sorting suggested tree, namely in the sequence search minimum value, then the first element and Swap; The iteration.CodePudding user response:
Example a lot of books!